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Home/ Questions/Q 6137435
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Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T17:43:32+00:00 2026-05-23T17:43:32+00:00

I’m trying to create a drop down box that is populated by an array.

  • 0

I’m trying to create a drop down box that is populated by an array. When I view my code the browser just displays pieces of the php code.

Here is what the browser displays:

'; foreach ($array as $value) { $html .= '
$value
'; } $html .= ''; return $html; } ?> 

Here is my code:

<html>
<head>
<title>test</title>
<?php

$cities = array( 'San Francisco', 'San Diego', 'Los Angeles');

function createDropDown($name, $array) {

  $html = '<select name=$name>';

  foreach ($array as $value) {
    $html .= '<option value="$value">$value</option>';
  }
  $html .= '</select>';
  return $html;
}
?>
</head>
<body>
<form>

<?php
createDropDown("cities", $cities);
?>

</form>
</body>
</html>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T17:43:33+00:00Added an answer on May 23, 2026 at 5:43 pm

    Most likely your server isn’t configured to treat .php files as PHP scripts, and is serving them up as html/plaintext. If you view-source the page this is happening on, you’ll probably get the full PHP source code. The <?php is seen as an opening HTML tag, which isn’t closed until just before the foreach loop, so all the intermediate text/code is “hidden” in HTML view.

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