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Home/ Questions/Q 8979913
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T19:57:20+00:00 2026-06-15T19:57:20+00:00

I’m trying to create a function which returns another function. I want separate information

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I’m trying to create a function which returns another function. I want separate information when each of the inner function is run, but this isn’t happening. I know that explanation is not great, so I’ve put together a small example.

            var testFn = function(testVal) {
                return (function(testVal) {
                    var test = testVal;

                    this.getVal = function() {
                        return test;
                    }

                    return that;

                })(testVal);
            }
            var a = testFn(4);
            var b = testFn(2);
            console.log(b.getVal(), a.getVal());

This outputs 2, 2. What I would like is 2, 4 to be output. I know this isn’t explained perfectly, so if it’s not clear what I’m trying to achieve, can someone explain why the variable seems to be shared across the two functions?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T19:57:21+00:00Added an answer on June 15, 2026 at 7:57 pm

    Like this ?

    var testFn = function(testVal) {
      var test = testVal
      return {
        getVal: function() {
          return  test
        }
      }   
    };
    
    var ab = testFn (4)
    var ac = testFn (2)
    
    console.log(ab.getVal(),ac.getVal()) //4 //2
    

    The problem in your code is this.getVal() / returning this

    because ‘this’ refers to the global scope / Window

    You are glubbering with the global namespace and overwriting Window.getVal() , the moment you are setting b = testFn (2)
    This results in overwriting as method getVal too because they both refer to the global Object and always share the same method getVal

    Therefore they share the same closure and are outputing 2

    console.log("The same: " + (Window.a === Window.b)) // true
    console.log("The same: " + (a === b)) // true

    you can see that if you change it a little:

            var testFn = function(testVal) {
              var x = {}
                return (function(testVal) {
                    var test = testVal;
                    x.getVal = function () {
                      return test;
                    }
                     return x
    
                })(testVal);
            }
            var a = testFn(4);
            var b = testFn(2);
            console.log(b.getVal(), a.getVal());//4 2
    

    it suddenly works because it results in 2 different Objects returned (btw you don’t even need the outer closure)
    console.log("The same: " + (a === b)) // false

    Here are the JSbins First / Second

    I hope you understand this, I’m not good in explaining things
    If theres anything left unclear, post a comment and I’ll try to update the answer

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