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Home/ Questions/Q 6476281
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T06:48:22+00:00 2026-05-25T06:48:22+00:00

I’m trying to create a global array whose size is determined by an external

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I’m trying to create a global array whose size is determined by an external parameter file at runtime.

I’ve seen other questions on this and tried:

int const Nt=1280;
double *Array = NULL;
Array = malloc(Nt * Nt * sizeof(double));

However, I get errors such as:

Error: Conflicting types for Array

Error: Initializer element is not constant

How can I create such a global array without needing to recompile every time I need to change its size?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T06:48:22+00:00Added an answer on May 25, 2026 at 6:48 am

    Assignment is not allowed at global scope. You have to do it in a function instead.

    int const Nt = 1280;
    double *Array = NULL;
    

    Assuming the above 2 statements are at global scope. They are examples of initialization because the statements assign value at the declaration itself. This is allowed at global scope and the initializers can be constant values, string literals or other variables accessible at this point.

    const int Nt ; // Just declaration
    Nt =  1280 ;   // Error. Assignment is not allowed at global scope.
    
    const char* myName = "CHP" ;
    int a[] = { 11,22,33,44,55 } ;
    

    And similarly in your example Array is just a declaration. Do the assignment in a function.

    void assignArray() {
    
        Array = malloc(Nt * Nt * sizeof(double));
    
        // ...
    
        printf("%d", sizeof(Array)/sizeof(Array[0]); // Size which is nothing but Nt*Nt
                                                     // 0 to (Nt * Nt) - 1
    }
    

    And regarding the segmentation fault, post more code.

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