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Home/ Questions/Q 241513
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T20:45:35+00:00 2026-05-11T20:45:35+00:00

I’m trying to create a piece of xml. I’ve created the dataclasses with xsd.exe.

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I’m trying to create a piece of xml. I’ve created the dataclasses with xsd.exe.
The root class is MESSAGE.

So after creating a MESSAGE and filling all its properties, I serialize it like this:

serializer = new XmlSerializer(typeof(Xsd.MESSAGE));
StringWriter sw = new StringWriter();
serializer.Serialize(sw, response);
string xml = sw.ToString();

Up until now all goes well, the string xml contains valid (UTF-16 encoded) xml.
Now I like to create the xml with UTF-8 encoding instead, so I do it like this:

Edit: forgot to include the declaration of the stream

serializer = new XmlSerializer(typeof(Xsd.MESSAGE));
using (MemoryStream stream = new MemoryStream())
{
    XmlTextWriter xtw = new XmlTextWriter(stream, Encoding.UTF8);
    serializer.Serialize(xtw, response);
    string xml = Encoding.UTF8.GetString(stream.ToArray());
}

And here comes the problem: Using this approach, the xml string is prepended with an invalid char (the infamous square).
When I inspect the char like this:

char c = xml[0];

I can see that c has a value of 65279.
Anybody has a clue where this is coming from?
I can easily solve this by cutting off the first char:

xml = xml.SubString(1);

But I’d rather know what’s going on than blindly cutting of the first char.

Anybody can shed some light on this? Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-11T20:45:35+00:00Added an answer on May 11, 2026 at 8:45 pm

    Here’s your code modified to not prepend the byte-order-mark (BOM):

    var serializer = new XmlSerializer(typeof(Xsd.MESSAGE));
    Encoding utf8EncodingWithNoByteOrderMark = new UTF8Encoding(false);
    XmlTextWriter xtw = new XmlTextWriter(stream, utf8EncodingWithNoByteOrderMark);
    serializer.Serialize(xtw, response);
    string xml = Encoding.UTF8.GetString(stream.ToArray());
    
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