Question

I’m trying to create a query that returns the closest (above) price for each id from table price for every date in table date.

date has these dates in it:

date
2010-11-25
2010-11-24
2010-11-10

price is as follows:

id  date        price
A   2010-11-26  24.99
A   2010-11-24  27.99
A   2010-11-13  22.12
B   2010-11-26  26.51
B   2010-11-24  23.24
B   2010-11-22  27.95

So for 2010-11-25 I should get

id  date        price
A   2010-11-26  24.99
B   2010-11-26  26.51

for 2010-11-10

id  date        price
A   2010-11-13  22.12
B   2010-11-22  27.95

for 2010-11-24

id  date        price
A   2010-11-24  27.99
B   2010-11-24  23.24

etc.

I believe getting the result for a given date is doable (maybe group by…having), however I am looking for a solution that does it for all the dates.

EDIT:

There was an error in the example, corrected…

Answer 1

I think you mean this, but there may be an error in your example. (Or misunderstand it).

select
  id, date,price
from
  (select
    p.id,
    p.date,
    p.price,
    dense_rank() over (partition by d.date, p.id order by p.date) as rank
  from
    date d
    inner join price p on p.date > d.date)
where
  rank = 1