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Home/ Questions/Q 6941837
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T12:56:12+00:00 2026-05-27T12:56:12+00:00

I’m trying to create a query that will return all the jobs published by

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I’m trying to create a query that will return all the jobs published by a specific company, and a count of the total people who applied to this job. the first part works fine – I get all the jobs and everything I need:

$query = "SELECT *,j.job_id as jid, c.name as city_name ".
         "FROM jobs j JOIN areas a ON a.area_id = j.job_area ".
         "JOIN positions p ON p.position_id = j.job_position ".
         "JOIN fields f ON f.id = j.job_field ".
         "JOIN cities c ON j.job_city = c.id ".
         "JOIN jobTypes jt ON j.job_type = jt.job_id " .
         "JOIN companies comp ON j.job_company = comp.company_id ".
         "LEFT JOIN jobApplications ja ON ".
              "ja.user_id = '".$_SESSION['user_id']."' AND ".
              "j.job_id = ja.job_id WHERE j.job_company='$company_id'";

The thing is, that I want to add each result row the number of applicants for the job from the jobApplications table… I tried to add a COUNT column to the query, which works great by itself:

SELECT COUNT(*) FROM jobApplications ja WHERE ja.job_id=j.job_id

when added to the first big query, I didn’t manage to make this work even on the syntax level, so i’m not sure if it works at all…

I tried to add the last query to the select area of the main query, but I always get a syntax error right after the ‘ja.job_id=j.job_id’ in the end of the count query…

Is this even possible ?

I hope the question is clear, I know there are many tables included here…
Thanks for the time and help!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:56:13+00:00Added an answer on May 27, 2026 at 12:56 pm

    i dont know your PK of jobApplications, but this might work.

    $query = "SELECT *,j.job_id as jid, c.name as city_name, COUNT(ja.<primary key>) ".
         "FROM jobs j JOIN areas a ON a.area_id = j.job_area ".
         "JOIN positions p ON p.position_id = j.job_position ".
         "JOIN fields f ON f.id = j.job_field ".
         "JOIN cities c ON j.job_city = c.id ".
         "JOIN jobTypes jt ON j.job_type = jt.job_id " .
         "JOIN companies comp ON j.job_company = comp.company_id ".
         "LEFT JOIN jobApplications ja ON ".
              "ja.user_id = '".$_SESSION['user_id']."' AND ".
              "j.job_id = ja.job_id WHERE j.job_company='$company_id' ".
         "GROUP By jid";
    
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