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Home/ Questions/Q 6147643
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T19:08:17+00:00 2026-05-23T19:08:17+00:00

I’m trying to create a row of divs with hidden images inside, when moused

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I’m trying to create a row of divs with hidden images inside, when moused over the middot will fade out, image will fade in, then fade out when the mouse leaves that div. I know I need to do something with the .hover function in jquery.

For example

<div id='1_1'>
 &midddot;
 <img src='image1_1.jpg' style='display:none'>
</div>
<div id='1_2'>
 &midddot;
 <img src='image1_2.jpg' style='display:none'>
</div>
<div id='1_3>
 &midddot;
 <img src='image1_3.jpg' style='display:none'>
</div>

Each div will represent a page of an article. So where id=’1_3′, that’d be a row 1, page 3, or id=’1_1′ would be row 1, page 1.

Just not sure how to structure the jquery to get this done.

FYI, I’m using php/mysql to output the info. So the above code would be one loop in that “while” statement. Subsequent loops would increase the row number (id=”2_1″, “2_2”, etc.).

Thanks for any advice.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T19:08:19+00:00Added an answer on May 23, 2026 at 7:08 pm

    Add a class to your divs to make them easier to select in jQuery.

    <div id='1_1' class='fade'>
       &midddot;
       <img src='image1_1.jpg' style='display:none'>
    </div>
    <div id='1_2' class='fade'>
       &midddot;
       <img src='image1_2.jpg' style='display:none'>
    </div>
    ...
    

    Then use the hover function:

     <script type="text/javascript">
        $(document).ready(function() {
           $("li.fade").hover(function(){  
               $("img", this).fadeIn();
               $("img", this).fadeOut();
           });
        });
      </script>
    
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