Im trying to create a small application where a user submit personal info and the data are saved on an Access DB.
The error that is returning does not make any sense because I am trying to insert the correct amount of values into the table.
The values are first,last,age, and gender.
This is my code followed by the error that i’m getting when i press the submit button.
Thanks for all your help.
<pre>
<%@ Page Language="C#" %>
<%@ Import Namespace="System.Data" %>
<%@ Import Namespace="System.Data.OleDb" %>
<script runat="server">
public void btnSubmit_Click(object sender, EventArgs e)
{
// Create and configure connection string.
OleDbConnection c = new OleDbConnection();
c.ConnectionString =
"Provider=Microsoft.ACE.OLEDB.12.0;" +
"Data Source=d:/ectserver/gnicolai/Database/application.accdb;";
// Open connection.
c.Open();
// Get data from textboxes.
string last = txtLastName.Text;
string first = txtFirstName.Text;
string gender = txtGender.Text;
int age = int.Parse(txtAge.Text);
// Compose SQL command string.
string sql = "INSERT INTO Applicant VALUES" +
"('" + last + "', '" + first +
"', '" + gender + "'," + age + ");";
// Show SQL insert statement.
litMessage.Text =
"Data submitted with SQL query string<br />" + sql;
// Create command object and execute insert statement.
OleDbCommand command = new OleDbCommand(sql, c);
command.ExecuteNonQuery();
// Close connection.
c.Close();
}
</script>
<html>
<head>
<title>grocery-display3.aspx Example</title>
<link rel="stylesheet" class="text/css"
href="../examples.css" />
<style type="text/css">
td { padding-left:0.15cm;
padding-right:0.15cm;
padding-top:0.15cm;
padding-bottom:0.15cm; }
</style>
</head>
<body>
<h2>PersonInfo3 Example</h2>
<p>Submit age, gender, and age for a person;
store this information in a database.
Retrieve this data with the ViewPersons page. </p>
<form id="frmSelect" runat="server">
<table>
<tr>
<td class="r">Last Name</td>
<td><asp:TextBox ID="txtFirstName" runat="server"
CssClass="ctrl" /></td>
</tr>
<tr>
<td class="r">First Name</td>
<td><asp:TextBox ID="txtLastName" runat="server"
CssClass="ctrl" /></td>
</tr>
<tr>
<td class="r">Gender</td>
<td><asp:TextBox ID="txtGender" runat="server"
CssClass="ctrl" /></td>
</tr>
<tr>
<td class="r">Age</td>
<td><asp:TextBox ID="txtAge" runat="server"
CssClass="ctrl" /></td>
</tr>
<tr>
<td> </td>
<td><asp:Button ID="btnSubmit" runat="server"
Text="Submit" CssClass="ctrl" Width="128px"
OnClick="btnSubmit_Click" /></td>
</tr>
</table>
<p><asp:RangeValidator ID="RangeValidator1" Type="Integer" runat="server"
ControlToValidate="txtAge" Display="Static" MinimumValue="0"
MaximumValue="130" ErrorMessage="Age must be between 0 and 130" /></p>
<p><asp:Literal ID="litMessage" runat="server" /></p>
</form>
</body>
</html>
</pre>
<strong>Error</strong>
<pre>
Server Error in '/' Application.
Number of query values and destination fields are not the same.
Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.
Exception Details: System.Data.OleDb.OleDbException: Number of query values and destination fields are not the same.
Source Error:
Line 32: // Create command object and execute insert statement.
Line 33: OleDbCommand command = new OleDbCommand(sql, c);
Line 34: command.ExecuteNonQuery();
Line 35:
Line 36: // Close connection.
Source File: d:\DePaul\Winter 2012\IT 330\Projects\Proj5-Nicolaides\Proj5-Nicolaides\Default.aspx Line: 34
Stack Trace:
[OleDbException (0x80004005): Number of query values and destination fields are not the same.]
System.Data.OleDb.OleDbCommand.ExecuteCommandTextErrorHandling(OleDbHResult hr) +992124
System.Data.OleDb.OleDbCommand.ExecuteCommandTextForSingleResult(tagDBPARAMS dbParams, Object& executeResult) +255
System.Data.OleDb.OleDbCommand.ExecuteCommandText(Object& executeResult) +188
System.Data.OleDb.OleDbCommand.ExecuteCommand(CommandBehavior behavior, Object& executeResult) +58
System.Data.OleDb.OleDbCommand.ExecuteReaderInternal(CommandBehavior behavior, String method) +161
System.Data.OleDb.OleDbCommand.ExecuteNonQuery() +113
ASP.default_aspx.btnSubmit_Click(Object sender, EventArgs e) in d:\DePaul\Winter 2012\IT 330\Projects\Proj5-Nicolaides\Proj5-Nicolaides\Default.aspx:34
System.Web.UI.WebControls.Button.OnClick(EventArgs e) +111
System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) +110
System.Web.UI.WebControls.Button.System.Web.UI.IPostBackEventHandler.RaisePostBackEvent(String eventArgument) +10
System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) +13
System.Web.UI.Page.RaisePostBackEvent(NameValueCollection postData) +36
System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +1565
</pre>
The ID field that I had on the database table was messing with my insert statement. After viewing the table in design view, I removed the “ID” field and my insert statement works as it should.