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Home/ Questions/Q 90963

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Editorial Team
Asked: May 10, 20262026-05-10T22:57:20+00:00 2026-05-10T22:57:20+00:00

I’m trying to create a type in an XML schema to enforce an element

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I’m trying to create a type in an XML schema to enforce an element with both:

  • A single attribute; and
  • Simple content matching an enumeration.

In an XML document, the element might look like:

<Operator Permutation='true'>   Equals </Operator> 

Where ‘Equals’ would be one of the enumerations.

Is this possible? If so, how?

I’ve tried doing in in XMLSpy with no success. If I make a simple type, it only allows content enumeraions without attributes. If I make a complex type, it only allows attributes without content enumerations.

Edit: Thanks, David. That works perfectly, but I just added this inside the restriction so the validation ignores line breaks:

<xs:whiteSpace value='collapse'/>
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1 Answer

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  1. 2026-05-10T22:57:21+00:00Added an answer on May 10, 2026 at 10:57 pm

    How about

      <xs:element name='Operator' type='MixedElement' />    <xs:complexType name='MixedElement'>     <xs:simpleContent>       <xs:extension base='EnumType'>         <xs:attribute name='Permutation' type='xs:boolean'>         </xs:attribute>       </xs:extension>     </xs:simpleContent>   </xs:complexType>    <xs:simpleType name='EnumType'>     <xs:restriction base='xs:string'>       <xs:enumeration value='Equals'/>       <xs:enumeration value='NotEquals'/>     </xs:restriction>   </xs:simpleType> 
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