Question

I’m trying to create an object which I want to populate inside a switch-case, but it’s out of my knowledge scope.

I have these constructors:

cObj::cObj()
{
}

cObj::cObj(std::string filename)
{
    //...
}

So, basically I want to call following method, create a pointer to the object, and populate it inside of my switch-case:

void someThing() {
    cObj myObj();

    switch (someValue)
        case 0:
            myObj("/some/path");
            break;
        ...
}

I assume my constructor is wrong since it does not really work.

How can I accomplish this?

Answer 1

When you create your object in this line

cObj myObj();

(btw. you probably don’t want these parentheses. You want to create an object, not declare a function).

you call the constructor. You can not call it again in switch statement.
You could create a separate method:

cObj::cObj()
{
}

void cObj::SetFilename(const std::string& filename) {
// ...
}

and use it like that:

void someThing() {
    cObj myObj;

    switch (someValue)
        case 0:
            myObj.SetFilename("/some/path");
            break;
        ...
}

I’m not sure what you’re trying to do, but maybe better way would be to first determine what the filepath is and then create the object?

void someThing() {
    std::string filepath = "default/path";

    switch (someValue)
        case 0:
            filepath = "some/path";
            break;
        ...

    cObj myObj(flepath);
}

You could also create a function that would make the decision what path to use and return the object: