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Home/ Questions/Q 8155627
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T16:43:28+00:00 2026-06-06T16:43:28+00:00

I’m trying to create an unique array regardless of its original order and using

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I’m trying to create an unique array regardless of its original order and using no module, this’s what I’ve come up with so far:

my @arr = qw(b a a c d g e f);
my %hash;
@hash{@arr}=();
say keys %hash;
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  1. Editorial Team
    Editorial Team
    2026-06-06T16:43:29+00:00Added an answer on June 6, 2026 at 4:43 pm

    Yes. Since hash keys are unique, this is one idiomatic way to do it. The number of ways to accomplish the same thing are many.

    You may also use a module, such as List::MoreUtils

    use strict;
    use warnings;
    
    use List::MoreUtils qw(uniq);
    print join ":", uniq qw(a a a b b c d);
    

    Output:

    a:b:c:d
    

    Some different ways to dedupe:

    my @arr = keys { map { $_ => 1 } qw(b a a c d g e f) };
    

    The curly braces creates an anonymous hash for keys, the map statement creates a list of key/value pairs.


    my @arr = dedupe(qw(a a b c d d e));
    
    sub dedupe {
        my %hash = map { $_ => 1 } @_;
        return keys %hash;
    }
    

    Same thing, but in subroutine form, and split into two lines. Note that both lists will be in a semi-random order, since hashes are unordered.

    The subroutine used by List::MoreUtils is equally simple, and perhaps preferable, since it will preserve the order of arguments. It still uses a hash, though.

    sub uniq {
        my %seen = ();
        grep { not $seen{$_}++ } @_;
    }
    
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