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Home/ Questions/Q 6075947
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T10:33:05+00:00 2026-05-23T10:33:05+00:00

I’m trying to create links to the same document with my XML and XSLT.

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I’m trying to create links to the same document with my XML and XSLT. I’m trying to use generate-id() to create an index then anchors for the respective items.

problem is, the element name is not the same in the XML but i wish to link to it.

for example

XML:

  <testresults>
      <test testname="ComparisonResult">
        <step stepname="Step1">
          <result>true</result>
        </step>
        <step stepname="Step2" >
          <result>true</result>
        </step>
      </test>
      <step stepname="results" stepresult="true">
        <drilldown>
          <taskresults>
            <testResults>
              <test testname="ComparisonResult_Step1">

              </test>
              <test testname="ComparisonResult_Step2">

              </test>
            </testResults>
          </taskresults>
        </drilldown>
      </step>

    </testresults>

XSLT:

   <?xml version="1.0" encoding="UTF-8" ?>
    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
      <xsl:template match="/">
        <html>
          <body>
            <font face="Arial" size="2">

            <h4>Steps</h4>


      <table border="1" bordercolor="#000000">
                  <tr bgcolor="#dccdc">
                    <th align="center">Task</th>
                  </tr>

        <xsl:for-each select="testresults/test/step">
                    <tr>
                      <td bgcolor="#F2F5A9">                  
                        <a href="#{generate-id(@stepname)}">
                        <xsl:value-of select="@stepname" />
                        </a>                    
                      </td>                   

                    </tr>       
                    </xsl:for-each>             
                    </table>

              <h2>Test Results</h2>  

                  <xsl:for-each select="testresults/step/drilldown/taskresults/testResults/test">

                <h3>
                <a name="{generate-id(@testname)}">
                  <xsl:value-of select="@testname" />
                  </a>
                </h3>

                </xsl:for-each>

                </xsl:template>

    </xsl:stylesheet>

Please ignore any mistakes, this is a quick mockup but you should get an idea of what im trying to do. I can’t get it to link to the corresponding item. I.e Step1 to ComparisonResult_Step1.

Any ideas

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T10:33:06+00:00Added an answer on May 23, 2026 at 10:33 am

    Frankly I don’t see why you need generate-id, as long as those names are unique then doing e.g.

    <xsl:for-each select="testresults/test/step">
                        <tr>
                          <td bgcolor="#F2F5A9">                  
                            <a href="#{concat(parent::test/@testname, '_', @stepname)}">
                            <xsl:value-of select="@stepname" />
                            </a>                    
                          </td>                   
    
                        </tr>       
                        </xsl:for-each>             
                        </table>
    
                  <h2>Test Results</h2>  
    
                      <xsl:for-each select="testresults/step/drilldown/taskresults/testResults/test">
    
                    <h3>
                    <a name="{@testname}">
                      <xsl:value-of select="@testname" />
                      </a>
                    </h3>
    
                    </xsl:for-each>
    

    should suffice.

    If you want to use generate-id then it only makes sense if you apply it to the same node.

    [edit] If you want to use generate-id then add <xsl:key name="k1" match="testresults/step/drilldown/taskresults/testResults/test" use="@testname"/> as a child of the xsl:stylesheet element, then change your code to e.g.

    <xsl:for-each select="testresults/test/step">
                        <tr>
                          <td bgcolor="#F2F5A9">                  
                            <a href="#{generate-id(key('k1', concat(parent::test/@testname, '_', @stepname)))}">
                            <xsl:value-of select="@stepname" />
                            </a>                    
                          </td>                   
    
                        </tr>       
                        </xsl:for-each>             
                        </table>
    
                  <h2>Test Results</h2>  
    
                      <xsl:for-each select="testresults/step/drilldown/taskresults/testResults/test">
    
                    <h3>
                    <a name="{generate-id()}">
                      <xsl:value-of select="@testname" />
                      </a>
                    </h3>
    
                    </xsl:for-each>
    
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