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Home/ Questions/Q 8853619
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T13:41:51+00:00 2026-06-14T13:41:51+00:00

I’m trying to create table (using migrations) with foreign key like this public function

  • 0

I’m trying to create table (using migrations) with foreign key like this

public function safeUp()
{
    $this->createTable('tbl_category', array(
        'id'=>'pk',
        'title'=>'string NOT NULL',
        'url'=>'string NOT NULL UNIQUE'
    ));
    $this->addForeignKey('FK_category', 'tbl_product', 'category_id', 'tbl_category', 'id', 'CASCADE', 'NO ACTION');    
}

It perfectly works in MySQL, but now I want to use SQLite and this code gives an error that in SQLite I can’t add foreign key to existing table, so I looked through the definition of createTable method:

public integer createTable(string $table, array $columns, string $options=NULL)

And tried to use $options param to add my foreign key there, but it generates this:

CREATE TABLE 'tbl_category' (
    "id" integer PRIMARY KEY AUTOINCREMENT NOT NULL,
    "title" varchar(255) NOT NULL,
    "url" varchar(255) NOT NULL UNIQUE
)
CONSTRAINT FK_category
FOREIGN KEY tbl_product(category_id)
REFERENCES tbl_category(id)
ON DELETE CASCADE ON UPDATE NO ACTION

Obviously, that “CONSTRAINT…” code should be inside these brackets, but it doesn’t. So how can I create this foreign key?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T13:41:53+00:00Added an answer on June 14, 2026 at 1:41 pm

    Explanation

    The function createTable is defined in the source code as:

    public function createTable($table, $columns, $options=null)
    {
        $cols=array();
        foreach($columns as $name=>$type)
        {
            if(is_string($name))
                $cols[]="\t".$this->quoteColumnName($name).' '.$this->getColumnType($type);
            else
                $cols[]="\t".$type;
        }
        $sql="CREATE TABLE ".$this->quoteTableName($table)." (\n".implode(",\n",$cols)."\n)";
        return $options===null ? $sql : $sql.' '.$options;
    }
    

    This tells me that all options are for things that would normally go after a Create statement (but before the final semi-colon), like ENGINE or CHARSET in MySQL. The SQLite syntax is just different and doesn’t allow such options.

    The addForeignKey function doesn’t work, it’s just not coded:

    public function addForeignKey($name, $table, $columns, $refTable, $refColumns, $delete=null, $update=null)
    {
        throw new CDbException(Yii::t('yii', 'Adding a foreign key constraint to an existing table is not supported by SQLite.'));
    }
    

    And SQLite doesn’t support altering a table to add a foreign key clause.

    Solution

    Long story short, you should put the foreign key clause in the column definition (in your product table, not your category table):

    $this->createTable('tbl_product', array(
        'id'=>'pk',
        'name'=>'string NOT NULL',
        'category_id'=>'integer NOT NULL REFERENCES tbl_category(id)'
    ));
    

    Addendum

    The idea with foreign keys is that the child table should declare it, not the parent table.

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