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Home/ Questions/Q 6957827
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T15:03:39+00:00 2026-05-27T15:03:39+00:00

I’m trying to define a cubic spline as a function in Mathematica 8 as

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I’m trying to define a cubic spline as a function in Mathematica 8 as I’ve got every P_{i} (which, of course, are polynomials of degree 3) for each interval [x_{i}, x_{i + 1}], i = 0, ..., n. What I want to do is to define s in the interval [x_{0}, x_{n + 1}] as s(x) = P_{i}(x) if x is in [x_{i}, x_{i+1}]. How can I do that as n varies? I was thinking of Piecewise but that didn’t work.

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  1. Editorial Team
    Editorial Team
    2026-05-27T15:03:39+00:00Added an answer on May 27, 2026 at 3:03 pm

    This does precisely what you ask, if I’m not mistaken. It’s a bit ugly though. There are better alternatives.

    n = 5;
    ClearAll[f];
    f[x_] = Piecewise[Table[{x^k, (k - 1)/n < x <= k/n}, {k, 0, n}]]
    

    enter image description here

    f[1/2]
    
    (* ==> 1/8 *)
    

    If you want to make the result dependent on the current state of the global variable n (which I wouldn’t advocate) thne you can replace the Set (=) in the definition of f with SetDelayed (:=), but this implies re-evaluating the Table for every call of f. Not that bad for small values of n, but I don’t like it. Results in that case look like this:

    n = 2; f[1/2]
    n = 5; f[1/2]
    
    (* ==>  1/2 
    
       ==>  1/8
    *)
    
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