Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 202169
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 11, 20262026-05-11T17:15:49+00:00 2026-05-11T17:15:49+00:00

I’m trying to delete all digits from a string. However the next code deletes

  • 0

I’m trying to delete all digits from a string.
However the next code deletes as well digits contained in any word, and obviously I don’t want that.
I’ve been trying many regular expressions with no success.

Thanks!


s = "This must not b3 delet3d, but the number at the end yes 134411"
s = re.sub("\d+", "", s)
print s

Result:

This must not b deletd, but the number at the end yes

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-11T17:15:49+00:00Added an answer on May 11, 2026 at 5:15 pm

    Add a space before the \d+.

    >>> s = "This must not b3 delet3d, but the number at the end yes 134411"
    >>> s = re.sub(" \d+", " ", s)
    >>> s
    'This must not b3 delet3d, but the number at the end yes '
    

    Edit: After looking at the comments, I decided to form a more complete answer. I think this accounts for all the cases.

    s = re.sub("^\d+\s|\s\d+\s|\s\d+$", " ", s)
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 229k
  • Answers 229k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer Some of the controls in the Compact Framework support BeginUpdate… May 13, 2026 at 1:44 am
  • Editorial Team
    Editorial Team added an answer Use the GridView properties to achieve this rather than applying… May 13, 2026 at 1:44 am
  • Editorial Team
    Editorial Team added an answer You can set your application to execute in a lower… May 13, 2026 at 1:44 am

Related Questions

I'm trying to decode HTML entries from here NYTimes.com and I cannot figure out
I want use html5's new tag to play a wav file (currently only supported
I ran into a problem. Wrote the following code snippet: teksti = teksti.Trim() teksti
In order to apply a triggered animation to all ToolTip s in my app,
I have a French site that I want to parse, but am running into

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.