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Home/ Questions/Q 7941291
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T23:37:30+00:00 2026-06-03T23:37:30+00:00

I’m trying to detect emoji in my php code, and prevent users entering it.

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I’m trying to detect emoji in my php code, and prevent users entering it.

The code I have is:

if(preg_match('/\xEE[\x80-\xBF][\x80-\xBF]|\xEF[\x81-\x83][\x80-\xBF]/', $value) > 0)
{
    //warning...
}

But doesn’t work for all emoji. Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-06-03T23:37:32+00:00Added an answer on June 3, 2026 at 11:37 pm
    if(preg_match('/\xEE[\x80-\xBF][\x80-\xBF]|\xEF[\x81-\x83][\x80-\xBF]/', $value) 
    

    You really want to match Unicode at a character level, rather than trying to keep track of UTF-8 byte sequences. Use the u modifier to treat your UTF-8 string on a character basis.

    The emoji are encoded in the block U+1F300–U+1F5FF. However:

    • many characters from Japanese carriers’ ‘emoji’ sets are actually mapped to existing Unicode symbols, eg the card suits, zodiac signs and some arrows. Do you count these symbols as ‘emoji’ now?

    • there are still systems which don’t use the newly-standardised Unicode emoji code points, instead using ad-hoc ranges in the Private Use Area. Each carrier had their own encodings. iOS 4 used the Softbank set. More info. You may wish to block the entire Private Use Area.

    eg:

    function unichr($i) {
        return iconv('UCS-4LE', 'UTF-8', pack('V', $i));
    }
    
    if (preg_match('/['.
        unichr(0x1F300).'-'.unichr(0x1F5FF).
        unichr(0xE000).'-'.unichr(0xF8FF).
    ']/u'), $value) {
        ...
    }
    
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