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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T04:56:39+00:00 2026-05-20T04:56:39+00:00

I’m trying to determine if two cubes overlap. I’ve read up on overlapping rectangles

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I’m trying to determine if two cubes overlap. I’ve read up on overlapping rectangles, but I’m not sure how to translate it into the third dimension.

My goal is to generate a number of randomly positioned and sized non-overlapping cubes.

These cubes are represented on a x,y,z Cartesian plane.

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  1. Editorial Team
    Editorial Team
    2026-05-20T04:56:39+00:00Added an answer on May 20, 2026 at 4:56 am

    You should be able to modify Determine if two rectangles overlap each other? to your purpose fairly easily.

    Suppose that you have CubeA and CubeB. Any one of 6 conditions guarantees that no overlap can exist:

    Cond1.  If A's left face is to the right of the B's right face,
               -  then A is Totally to right Of B
                  CubeA.X2 < CubeB.X1
    Cond2.  If A's right face is to the left of the B's left face,
               -  then A is Totally to left Of B
                  CubeB.X2 < CubeA.X1
    Cond3.  If A's top face is below B's bottom face,
               -  then A is Totally below B
                  CubeA.Z2 < CubeB.Z1
    Cond4.  If A's bottom face is above B's top face,
               -  then A is Totally above B
                  CubeB.Z2 < CubeA.Z1
    Cond5.  If A's front face is behind B's back face,
               -  then A is Totally behind B
                  CubeA.Y2 < CubeB.Y1
    Cond6.  If A's left face is to the left of B's right face,
               -  then A is Totally to the right of B
                  CubeB.Y2 < CubeA.Y1
    

    So the condition for no overlap is:

    Cond1 or Cond2 or Cond3 or Cond4 or Cond5 or Cond6
    

    Therefore, a sufficient condition for Overlap is the opposite (De Morgan)

    Not Cond1 AND Not Cond2 And Not Cond3 And Not Cond4 And Not Cond5 And Not Cond6
    
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