Question

I’m trying to display information about an object, concretely a customer. I mean name, last name, telephone number, adress, …. that is the result by a query on my database.

I want to display this on a ListView, so better if my activity inherit of a ListActivity because ListView is self-contained by default.

I do the next: I have a class called Customer that saves all information by the query (Cursor) that only return one record(customer) and I don’t know how to pass this object ,I don’t find the most appropriate adapter.

Can I do this by this way or I must convert this object into an ArrayList that contains all information and, in fact, use ArrayAdapter for my adapter?

Anyone knows how to do this??

Thanks.

Answer 1

Once you have your cursor queried you should do something like this

String[] from = new String[]{"FirstName"};
int[] to = new int[]{R.id.row};

SimpleCursorAdapter sca = new SimpleCursorAdapter(this, R.layout.row_item, cur, from, to);
setListAdapter(sca);

check here the documentation for SimpleCursorAdapter.
If you need to do something more complicated with your views you should implement your own custom Cursor adapter:

public class ExampleCursorAdapter extends CursorAdapter {
    public ExampleCursorAdapter(Context context, Cursor c) {
        super(context, c);
    }

    @Override
    public void bindView(View view, Context context, Cursor cursor) {
        TextView summary = (TextView)view.findViewById(R.id.summary);
        summary.setText(cursor.getString(
                cursor.getColumnIndex(ExampleDB.KEY_EXAMPLE_SUMMARY)));
    }

    @Override
    public View newView(Context context, Cursor cursor, ViewGroup parent) {
        LayoutInflater inflater = LayoutInflater.from(context);
        View v = inflater.inflate(R.layout.item, parent, false);
        bindView(v, context, cursor);
        return v;
    }
}