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Home/ Questions/Q 6566121
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T14:10:45+00:00 2026-05-25T14:10:45+00:00

I’m trying to do it this way: template <typename T> ostream &operator<<(ostream &os, T

  • 0

I’m trying to do it this way:

template <typename T>
ostream &operator<<(ostream &os, T &arr)
{ /*...*/ }

But can T represent an array? Is it correct to overload the << operator for an array?


EDIT:

According to Kerrek SB’s advice, here is my implementation for <<:

template <typename T, unsigned int N>
ostream &operator<<(ostream &os, const T (&arr)[N])
{
    int i;
    for(i = 0; i < N; i++)
        os << arr[i] << " ";
    os << endl;
    return os;
}

Is my implementation right? I got a compilation error.

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  1. Editorial Team
    Editorial Team
    2026-05-25T14:10:45+00:00Added an answer on May 25, 2026 at 2:10 pm

    You could do this:

    template <typename T, unsigned int N>
    std::ostream & operator<<(std::ostream & os, const T (&arr)[N])
    {
      // ..
      return os;
    }
    

    This works only for compile-time arrays, of course. Note that you are not allowed to instantiate this template when T is a built-in type or a type in the std namespace!

    Probably best to make this inline if possible, since you’ll cause a separate instantiation for every N. (The pretty printer has an example of this.)

    You will notice, though, that the blanket template introduces an ambiguity, because os << "Hello" now has two possible overloads: the template matching const char (&)[6], and the (non-template) overload for the decay-to-pointer const char *, which both have identical conversion sequences. We can resolve this by disabling our overload for char arrays:

    #include <ostream>
    #include <type_traits>
    
    template <typename T, unsigned int N>
    typename std::enable_if<!std::is_same<T, char>::value, std::ostream &>::type
    operator<<(std::ostream & os, const T (&arr)[N])
    {
      // ..
      return os;
    }
    

    In fact, to be even more general you can also make the basic_ostream parameters template parameters:

    template <typename T, unsigned int N, typename CTy, typename CTr>
    typename std::enable_if<!std::is_same<T, char>::value,
                            std::basic_ostream<CTy, CTr> &>::type
    operator<<(std::basic_ostream<CTy, CTr> & os, const T (&arr)[N])
    {
      // ..
      return os;
    }
    

    In view of the fact that T must be a user-defined type, you could even replace is_same<T, char> with is_fundamental<T> to get a bit more checking (but users still must not use this for arrays of standard library types).

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