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Home/ Questions/Q 8098863
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T22:12:40+00:00 2026-06-05T22:12:40+00:00

I’m trying to do some simple things in C and I’m confused. The program

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I’m trying to do some simple things in C and I’m confused.
The program is simple, the main function is handling thread according to a job que struct. Its opening up to 4 thread at a time. Around 300 threads till the end. The thread function is always the same but the args are different.

The hole code is bit long to paste here so I will paste some parts.

thread is opening as with the following parameter:

pthread_attr_init(&attr);
pthread_attr_setdetachstate(&attr, PTHREAD_CREATE_DETACHED); 
pthread_create(&pth, &attr, dothejob, (void *) varis);

the thread called function

void *dothejob(void * varis){
unsigned char * arr1;
arr1 = (unsigned char*) calloc(3000000, sizeof (unsigned char));
unsigned char * arr2;
arr2 = (unsigned char*) calloc(3000000, sizeof (unsigned char));
// doing some calculations and comparisons and stuff
unsigned int topten[10];  
// <---- here topten has some values from previous threads, but why ? 
// picking top ten and putting it in the var topten[
free(arr1);
free(arr2);
pthread_detach(pthread_self());
}

If someone knows it please help me. Thank you in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-05T22:12:41+00:00Added an answer on June 5, 2026 at 10:12 pm

    When you write this inside a function:

    unsigned int topten[10];  
    

    The array values are not initialized to 0. They contain whatever happens to be in memory at location topten points to. It is undefined behaviour to use values from your topten array without writing your own new values into the array first. If you want your array to be filled with 0s you should initialize it like so:

    unsigned int topten[10] = {0};
    
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