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Home/ Questions/Q 6994831
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T19:56:32+00:00 2026-05-27T19:56:32+00:00

I’m trying to do some very basic arithmetic and am getting hung up. I’m

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I’m trying to do some very basic arithmetic and am getting hung up. I’m pulling variables from a URL like this:

http://mysite.com/page.php?var1=100&var=5

This is the basic /page.php code I’m using:

<?php
$var1 = "var1";
$var2 = "var2";
$divided_amount = $var1/$var1;
?>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
        <title>Derp</title>
</head>
<body style="background-color: #fff; text-align: center;">

        <div style="text-align: center; width: 1000px; background-color: #fff; margin: auto;">

<p>This should be the divided amount: <?php echo $divided_amount ?> </p>


</body>
</html>

However, I end up getting this error message:

Warning: Division by zero in /derp.php on line 4

Is this even possible to do with passed variables? If so, where am I going wrong? Any help is greatly appreciated!

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  1. Editorial Team
    Editorial Team
    2026-05-27T19:56:33+00:00Added an answer on May 27, 2026 at 7:56 pm

    You are dividing a string by another string. Try replacing your PHP code with this:

    <?php
    $var1 = $_GET["var1"];
    $var2 = $_GET["var2"];
    if(is_numeric($var1) && is_numeric($var2) && $var2 != 0)
    {
        // Perform division only if the variables are numeric and $var2 is not 0
        $divided_amount = $var1/$var2;
    }
    else
    {
        // Value to be displayed if division is not possible.
        $divided_amount = 0;
    }
    ?>
    
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