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Home/ Questions/Q 8912919
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T04:20:11+00:00 2026-06-15T04:20:11+00:00

I’m trying to do something as followed float* A = fill_float(); //in other words

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I’m trying to do something as followed

float* A = fill_float(); //in other words A is full
float aIn2D[n/p][n] = &A; //the 2d array should be able to alter the 1d

I tried the above but wouldn’t compile (something about not being able to make the size variable length?). also tried

float** aIn2D = &A

But in retrospect that was nonsensical as how would the float** magically know I want a row, column distribution of [n/p][n] (i don’t think it does since the program crashes right at the first access of aIn2D).

So does anyone know how to do something like float aIn2D[n/p][n] = &A; in c?

edit: One more thing, I for sure know the size from [n/p][n] is going to be the size of the amount of data A is holding.

edit2: A very big aspect is that both arrays point to the same memory location, aIn2D is just a way for me to easily access A in methods that follow.

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  1. Editorial Team
    Editorial Team
    2026-06-15T04:20:12+00:00Added an answer on June 15, 2026 at 4:20 am

    Assuming n_rows and n_cols are variables, let’s say you have an n_rows*n_cols 1D array of floats that you want to treat as an n_rows x n_cols 2D array.

    With C99, which supports variable-sized arrays, you actually can do pretty much what you want:

    float* A = fill_float();
    float (*aIn2D)[n_cols] = (float (*)[n_cols])A;
    

    Otherwise, you can do something like this:

    float *A = fill_float();
    float **aIn2D = malloc(n_rows*sizeof(float*));
    
    {
      int i=0;
      for (; i!=n_rows; ++i) {
        aIn2D[i] = A + i*n_cols;
      }
    }
    
    // Use aIn2D[row][col]
    
    free(aIn2D);
    
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