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Home/ Questions/Q 4078302
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T17:39:26+00:00 2026-05-20T17:39:26+00:00

I’m trying to do the following: select i.FirstName, i.LastName, COUNT(1) from ( select u.Id,

  • 0

I’m trying to do the following:

select i.FirstName, i.LastName, COUNT(1) from (
    select u.Id, uw.WidgetId from [DB].[dbo].[Widgets] w inner join
     UserWidgets uw on w.Id = uw.WidgetId inner join
     Users u on uw.UserId = u.Id
     where uw.WidgetId in ('29017318-FD89-4952-A3A2-8405BD5C5C44', 
                           'BDB7D25C-0794-4965-842D-E6D03A250418',
                          'CB4553AC-A47B-4AA6-9231-5C59C8F97655')
     group by u.Id, uw.WidgetId
     ) a
 inner join [Db2].[dbo].[Identities] i on a.Id = i.IdentityId
 group by i.LastName, i.FirstName
 order by i.LastName, i.FirstName

What I want is to ensure that the “In” statement requires that the User ONLY has those 3 Id’s. No more, no less.

What is the best way to do this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T17:39:26+00:00Added an answer on May 20, 2026 at 5:39 pm

    Try:

    select i.FirstName, i.LastName, COUNT(1) from (
        select u.Id, uw.WidgetId from [DB].[dbo].[Widgets] w inner join
         UserWidgets uw on w.Id = uw.WidgetId 
                        and uw.WidgetId in ('29017318-FD89-4952-A3A2-8405BD5C5C44', 
                               'BDB7D25C-0794-4965-842D-E6D03A250418',
                              'CB4553AC-A47B-4AA6-9231-5C59C8F97655')
         inner join Users u on uw.UserId = u.Id
         left join UserWidgets uw2 on uw2.userid = u.id
                        and uw2.WidgetId not in ('29017318-FD89-4952-A3A2-8405BD5C5C44', 
                               'BDB7D25C-0794-4965-842D-E6D03A250418',
                              'CB4553AC-A47B-4AA6-9231-5C59C8F97655')
         where uw2.widgetid is null
         group by u.Id, uw.WidgetId
         ) a
     inner join [Db2].[dbo].[Identities] i on a.Id = i.IdentityId
     group by i.LastName, i.FirstName
     having count(1) = 3
     order by i.LastName, i.FirstName
    
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