Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3305012
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 17, 20262026-05-17T21:07:21+00:00 2026-05-17T21:07:21+00:00

I’m trying to do this: class Foo(Base): id = Column(Integer, primary_key=True) class Bar(Foo): id

  • 0

I’m trying to do this:

class Foo(Base):
    id = Column(Integer, primary_key=True)

class Bar(Foo):
    id = Column(Integer, primary_key=True)

class FooBarAssociation(Base):
    foo_id = Column(Integer, ForeignKey('foo_table.id'))
    bar_id = Column(Integer, ForeignKey('bar_table.id'))

    foo = relationship(Foo, backref=...)
    bar = relationship(Bar, backref=...)

…but I get errors like this:

Could not determine join condition between parent/child tables on relationship FooBarAssociation.foo.  Specify a 'primaryjoin' expression.  If this is a many-to-many relationship, 'secondaryjoin' is needed as well.

I’ve tried specifying foreign_keys and primary_join-s in the relationship declarations, but all for naught. Help? Is the inheritance of Bar from Foo messing with me?

thanks!

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-17T21:07:21+00:00Added an answer on May 17, 2026 at 9:07 pm

    Following should work (exactly what the error tells: missing primaryjoin):

    class FooBarAssociation(Base):
        foo_id = Column(Integer, ForeignKey('foo_table.id'), primary_key = True, )
        bar_id = Column(Integer, ForeignKey('bar_table.id'), ForeignKey('foo_table.id'), primary_key = True, )
    
        foo = relationship(Foo, backref="bars", primaryjoin=(foo_id==Foo.id))
        bar = relationship(Bar, backref="foos", primaryjoin=(bar_id==Bar.id))
    

    As you can see, there are two foreign keys on the bar_id column. This could be required due to inheritance, or you might remove one. But if you do not store any other information apart of the many-to-many relationship, then you might consider Association Proxy instead.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
Basically, what I'm trying to create is a page of div tags, each has
I am trying to understand how to use SyndicationItem to display feed which is
I'm trying to decode HTML entries from here NYTimes.com and I cannot figure out
link Im having trouble converting the html entites into html characters, (&# 8217;) i
Does anyone know how can I replace this 2 symbol below from the string
this is what i have right now Drawing an RSS feed into the php,
I am trying to loop through a bunch of documents I have to put
I have this code: - (void)parser:(NSXMLParser *)parser foundCDATA:(NSData *)CDATABlock { NSString *someString = [[NSString
I have some data like this: 1 2 3 4 5 9 2 6

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.