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Home/ Questions/Q 7045931
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T02:35:25+00:00 2026-05-28T02:35:25+00:00

I’m trying to draw a simple line graph which would use values from the

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I’m trying to draw a simple line graph which would use values from the database. At the moment I have a function which gets my data as it should and I also have another .php file which should be the one where the image is constructed.

I’ve basically used the example from here and it works if the values are typed manually. Nevertheless when I try to call $arrval = functionToGetValues("$keyword"); it just won’t work it won’t draw anything. I’m guessing it’s mostly because the GD is so messed up because it doesn’t seem to work too good even with normal php commands.

I think it’s unnecessary to post exact code because functionToGetValues works and it just returns an array of values.

I also tried to play with scopes like initializing the $arrvals in functionToGetValues() but it didn’t work. My calling sequence was:

/main.php

include "conn.php";

....

dbquery("$keyword");

//in dbquery($keyword)...

$arrval = array(...);

for($i=1; $i<30;$i++)
{
     $sql =  mysql_query("SELECT * FROM table WHERE data LIKE '%$keyword%'") or die("Query error: ". mysql_error());;
     $total = mysql_num_rows($sql);

$arrval [$i] = $total;

}

<img src='imgdraw.php?keyword=$keyword'vspace='50'/>";

I also tried this type of solution but the include “conn.php” just doesn’t seem to work with GD -_-. I can’t find out the reason 🙁

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  1. Editorial Team
    Editorial Team
    2026-05-28T02:35:25+00:00Added an answer on May 28, 2026 at 2:35 am

    If you dont have much luck with GD You could use google’s chart tools for generating graphs. I have always found it easy to use and well documented and the graphs it generates look pretty good.

    http://code.google.com/apis/chart/interactive/docs/gallery/linechart.html

    You would query your database then build up an array before exporting it inside a javascript tag with the a php array with echo json_decode();

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