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Home/ Questions/Q 6187545
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T02:04:37+00:00 2026-05-24T02:04:37+00:00

I’m trying to dynamically allocate (it’s not so dynamic as it is right now,

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I’m trying to dynamically allocate (it’s not so dynamic as it is right now, but eventually it will be) memory for objects in a very simple C++ program. I’m new to classes and have only recently started playing with C++, leaving C behind. Here’s the code:

#include <iostream>
using namespace std;

class Test {
  private:
    int i;
  public:
    Test(int);
    ~Test();
    void print();
};

Test::Test(int ii) { i = ii; }
Test::~Test() { i=0; cout << "deconstructor called...value of i= " << i << endl; }
void Test::print() { cout << "value of i= " << i << endl; }

int main()
{
  Test a(10),*b,*c;
  //a.print(); // this works

  b = new Test(12);
  //b->print(); // this works as well

  for (int i=0; i<2; i++)
    c = new Test(i);

  c->print(); /* this shows that the value of i=1 .. should be 0? */
  c[0].print(); /* as expected (I guess), this prints i=1 as well... [expected because c->print() shows i=1 also */
  c[1].print(); /* shows value of i=0... */

  //delete []c; /* this fails miserably, but `delete c` works, why :( */

}

A lot of my confusion is actually included within comments in the code itself. I’m basically trying to have an array c where each element of the array is an object of itself.

The behavior of the code that I’m getting is described in the comments.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T02:04:37+00:00Added an answer on May 24, 2026 at 2:04 am

    Perhaps we should look at the declarations, expanded you have:

    Test a(10);
    Test *b;
    Test *c;
    

    You have defined b and c as pointer-to-Test, but you seem to want c to be an array of pointer-to-test. The declaration for c you intended was likely:

    Test **c;
    

    which you would initialize:

    c = new Test*[2];
    
    for (int i=0; i<2; i++)
       c[i] = new Test(i);
    

    and which you would access thus:

    c[0]->print();
    c[1]->print();
    
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