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Home/ Questions/Q 6701035
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T06:53:08+00:00 2026-05-26T06:53:08+00:00

I’m trying to execute a search of sorts (using JavaScript) on a list of

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I’m trying to execute a search of sorts (using JavaScript) on a list of strings. Each string in the list has multiple words.

A search query may also include multiple words, but the ordering of the words should not matter.

For example, on the string “This is a random string”, the query “trin and is” should match. However, these terms cannot overlap. For example, “random random” as a query on the same string should not match.

I’m going to be sorting the results based on relevance, but I should have no problem doing that myself, I just can’t figure out how to build up the regular expression(s). Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-26T06:53:08+00:00Added an answer on May 26, 2026 at 6:53 am

    It probably isn’t a good idea to do this with just a regular expression. A (pure, computer science) regular expression “can’t count”. The only “memory” it has at any point is the state of the DFA. To match multiple words in any order without repeat you’d need on the order of 2^n states. So probably a really horrible regex.

    (Aside: I mention “pure, computer science” regular expressions because most implementations are actually an extension, and let you do things that are non-regular. I’m not aware of any extensions, certainly none in JavaScript, that make doing what you want to do any less painless with a single pattern.)

    A better approach would be to keep a dictionary (Object, in JavaScript) that maps from words to counts. Initialize it to your set of words with the appropriate counts for each. You can use a regular expression to match words, and then for each word you find, decrement the corresponding entry in the dictionary. If the dictionary contains any non-0 values at the end, or if somewhere a long the way you try to over-decrement a value (or decrement one that doesn’t exist), then you have a failed match.

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