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Home/ Questions/Q 6762421
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T14:19:26+00:00 2026-05-26T14:19:26+00:00

I’m trying to execute this code : import re pattern = r(\w+)\*([\w\s]+)*/$ re_compiled =

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I’m trying to execute this code :

import re
pattern = r"(\w+)\*([\w\s]+)*/$"
re_compiled = re.compile(pattern)
results = re_compiled.search('COPRO*HORIZON 2000                 HOR')
print(results.groups())

But Python does not respond. The process takes 100% of the CPU and does not stop. I’ve tried this both on Python 2.7.1 and Python 3.2 with identical results.

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  1. Editorial Team
    Editorial Team
    2026-05-26T14:19:27+00:00Added an answer on May 26, 2026 at 2:19 pm

    Your regex runs into catastrophic backtracking because you have nested quantifiers (([...]+)*). Since your regex requires the string to end in / (which fails on your example), the regex engine tries all permutations of the string in the vain hope to find a matching combination. That’s where it gets stuck.

    To illustrate, let’s assume "A*BCD" as the input to your regex and see what happens:

    1. (\w+) matches A. Good.
    2. \* matches *. Yay.
    3. [\w\s]+ matches BCD. OK.
    4. / fails to match (no characters left to match). OK, let’s back up one character.
    5. / fails to match D. Hum. Let’s back up some more.
    6. [\w\s]+ matches BC, and the repeated [\w\s]+ matches D.
    7. / fails to match. Back up.
    8. / fails to match D. Back up some more.
    9. [\w\s]+ matches B, and the repeated [\w\s]+ matches CD.
    10. / fails to match. Back up again.
    11. / fails to match D. Back up some more, again.
    12. How about [\w\s]+ matches B, repeated [\w\s]+ matches C, repeated [\w\s]+ matches D? No? Let’s try something else.
    13. [\w\s]+ matches BC. Let’s stop here and see what happens.
    14. Darn, / still doesn’t match D.
    15. [\w\s]+ matches B.
    16. Still no luck. / doesn’t match C.
    17. Hey, the whole group is optional (...)*.
    18. Nope, / still doesn’t match B.
    19. OK, I give up.

    Now that was a string of just three letters. Yours had about 30, trying all permutations of which would keep your computer busy until the end of days.

    I suppose what you’re trying to do is to get the strings before/after *, in which case, use

    pattern = r"(\w+)\*([\w\s]+)$"
    
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