Question

I’m trying to expand and add a new object to a array inside a function and have that array be effected outside the function as well (the arrays pointer is sent as a parameter).

void addMedia(Media* medias[], int &nrOfMedias, string title, int publYear, string author, int nrOfPages)
{
    Media** tempArray = new Media*[nrOfMedias +1];
    for(int i = 0; i < nrOfMedias; i++)
    {
        tempArray[i] = medias[i];
    }
    delete [] medias;
    medias = tempArray;
    delete [] tempArray;
    medias[nrOfMedias] = new Book(title, publYear, author, nrOfPages);
    nrOfMedias++;
}

This code works great inside the function but when I get outside it the array is still empty. As i understand this it’s because the pointer is changed inside the function but how can i expand the array without having it change the pointer?

(I can not change the return data type or the parameters, assignment requirements.)

Answer 1

Do change medias = tempArray; to *medias = tempArray;, make it compile, polish your memory management (consider, what really should be freed, what not).