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Home/ Questions/Q 9233439
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T06:33:14+00:00 2026-06-18T06:33:14+00:00

I’m trying to fetch all rows to an array variable array that i want

  • 0

I’m trying to fetch all rows to an array variable

array that i want is like this

$data1 = array('fields'=>array(
        array(
          'id' => 1,
          'nama_file' => "sunset.jpg",
          'judul' => "Sunset",
          'isi' => "Matahari terbenam indah sekali",           
        ),
        array(
          'id' => 2,
          'nama_file' => "water_lilies.jpg",
          'judul' => "Bunga Lilly",
          'isi' => "Bunga lilly air sangat indah",           
        ),)

And I’ve done this:

$q = $this->db->query('select id, nama_file, judul, isi from tfoto where dihapus ="T" ');
$data1=array('fields');
foreach($q->result() as $row) {


$data1['fields']=array('id'=>$row->id,'nama_file'=>$row->nama_file,'judul'=>$row->judul, 'isi'=>$row->isi);
}

test output:

<?php 
foreach($fields as $field){ 
echo $field['nama_file'];
.
.
.
};?>

and I got Message: Illegal string offset ‘nama_file’;’judul’; etc.

I am a newbie to MySQL/PHP, so forgive me if this is a very basic question. I tried looking all over but I could not find an answer to it.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T06:33:15+00:00Added an answer on June 18, 2026 at 6:33 am

    This line:

    $data1['fields']=array('id'=>$row->id,'nama_file'=>$row->nama_file,'judul'=>$row->judul, 'isi'=>$row->isi);
    

    Should be:

    $data1['fields'][] = array('id'=>$row->id,'nama_file'=>$row->nama_file,'judul'=>$row->judul, 'isi'=>$row->isi);
    

    Because you have to append new arrays to $data1 and not replacing it.

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