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Home/ Questions/Q 7585701
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T19:14:24+00:00 2026-05-30T19:14:24+00:00

I’m trying to figure how to return a row with the associated value when

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I’m trying to figure how to return a row with the associated value when using the JOIN syntax, firstly it should check the links table to see if the row is NULL, if it’s not NULL use that for the JOIN e.g. ON links.role_id = roles.role_id if the row is NULl. If it’s NULL then use the people table.

My syntax:

SELECT roles.role_name
FROM
(
    people_links links

    LEFT OUTER JOIN people people ON links.person_id = people.person_id

    LEFT OUTER JOIN roles roles ON links.role_id = roles.role_id OR links.role_id = people.role_id
)

Basically when joining and using the ON syntax with the role_id, it will return the associated value from the roles table that is used from the role_id so it should rely on the links table first, check if links.role_id is NULL then return people.role_id else links.role_id for the JOIN to get the role_name.

When I run this query, it uses the role_id from the people table first, when it should look in the links table first.

I tried using COALESCE but that will only return the role_id when it should return role_name, so for example (pseudo code):

SELECT IF(links.role_id IS NOT NULL) links.role_id ELSE people.role_id ENDIF as join_value
FROM
(
    people_links links

    LEFT OUTER JOIN people people ON links.person_id = people.person_id

    LEFT OUTER JOIN roles roles ON roles.role_id = join_value
)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T19:14:25+00:00Added an answer on May 30, 2026 at 7:14 pm

    You could write IF(links.role_id IS NOT NULL, links.role_id, people.role_id) — that’s the closest thing to your pseudocode — but it’s more idiomatic to write COALESCE(links.role_id, people.role_id).

    For information on IF, see §11.4 “Control Flow Functions” in the MySQL Reference Manual; for information on COALESCE, see §11.3.2 “Comparison Functions and Operators”.

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