Question

I’m trying to figure out how to build a query using Yii’s CDbCriteria that would be equivalent to the following:

 SELECT 
        * 
FROM 
        user u 
JOIN ( 
        SELECT * 
        FROM skill_assessment s 
        WHERE s.skill = 'HTML' 
        AND s.score >= 80 
) b ON 
        (u.id = b.userId) 
JOIN ( 
        SELECT * 
        FROM skill_assessment s 
        WHERE s.skill = 'CSS3' 
        AND s.score >= 80
) c ON 
        (u.id = c.userId);
etc...

Here’s what I have so far, that isn’t working:

$criteria = new CDbCriteria();
$criteria->alias = "u";
$criteria->select = "*";
$criteria->join = "JOIN skill_assessment s ON (u.id=s.userId)";
for($i = 0; $i < count($skill_filters); $i++) {
    $criteria->addCondition("s.skill='".$skill_filters[$i]->skill."' AND s.score >= ".$skill_filters[$i]->level);
}

$users = UserModel::model()->findAll($criteria);

Any help would be greatly appreciated.
Thanks in advance.

EDIT:
I was able to build out the sql query as a string and use findAllBySql, which returned the correct UserModels that matched my search criteria, the problem is that I haven’t been able to get it to return the related SkillAssessmentModels. They don’t come back either with the initial query, like this:

$users = UserModel::model()->with('skill_assessments')->findAllBySql($sql);

nor if I get the results like this:

$users = UserModel::model->findAllBySql($sql);
foreach($users as $user)
{
     $user->skill_assessments = $user->getRelated('skill_assessments');
}

Any thoughts on how I can get those related models?
The strange thing is that elsewhere in my application, I CAN get the related models if I do this:

$user = UserModel::model->findByPk($id);
$user->skill_assessments->getRelated('skill_assessments');

Answer 1

Thanks a lot to Boris Belenski!
What you suggested wasn’t quite what I needed, but it did get me to what I needed. Here is what I ended up with that works:

$str = "abcdefghijklmnopqrstuvwxyz";
            $idxs = str_split($str);

            $criteria = new CDbCriteria();
            $criteria->alias = "u";
            $joins = array();
            for($i = 0; $i < count($skill_filters); $i++)
            {
                $joins[] = " JOIN (SELECT * FROM skill_assessment s WHERE s.skill = '" . $skill_filters[$i]->skill ."' AND s.score >= " . $skill_filters[$i]->level . ") " . $idxs[$i] . " ON (u.id = " . $idxs[$i] . ".userId) ";
            }

            $criteria->join = join(' ', $joins);
            $users = UserModel::model()->findAll($criteria);
            foreach($users as $user)
            {
                $user->skill_assessments = $user->getRelated('skill_assessments');
            }

The really key part is that $joins array.
This will allow you to get all the users that match ALL the criteria for row matches in the skill_assessments table.

Also, I could probably lazily load the skill assessments in the View in a normal view, but I need to get all the skill_assessments for each user now in order to pass them back in an ajax response with the user.