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Home/ Questions/Q 8618985
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T06:14:09+00:00 2026-06-12T06:14:09+00:00

I’m trying to figure out how to clone an Ext.data.Store without keeping the old

  • 0

I’m trying to figure out how to clone an Ext.data.Store without keeping the old reference.

Let me explain better with some code. Here’s the source store:

var source = Ext.create ('Ext.data.Store', {
    fields: ['name', 'age'] ,
    data: [
        {name: 'foo', age: 20} ,
        {name: 'boo', age: 30} ,
        {name: 'too', age: 10} ,
        {name: 'yoo', age: 80} ,
        {name: 'zoo', age: 30}
    ]
});

Follows an example of what I want to do:

var target = source;
target.removeAll ();
// Here I need to have target empty and source unchanged
// But in this case, source is empty as well

Now, in the above example the copy is done by reference while I need to do it by value.
So I found Ext.clone () in the docs but it seems it doesn’t work for complex object, like Ext.data.Store:

var target = Ext.clone (source);
target.removeAll ();
// source is still empty

Then I tried with Ext.data.Model.copy () but the only way to do it work is this:

var target = Ext.create ('Ext.data.Store', {
    fields: ['name', 'age']
});

source.each (function (model) {
    target.add (model.copy ());
});

Now, for my reasons, I don’t want to instantiate another Ext.data.Store, so I want to avoid this:

var target = Ext.create ('Ext.data.Store', {
    fields: ['name', 'age']
});

I’d like to have something like this:

var target;

source.each (function (model) {
    target.add (model.copy ());
});

But, obviously, it doesn’t work.

So, how can I clone the source store?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T06:14:11+00:00Added an answer on June 12, 2026 at 6:14 am

    ExtJS 3.x solution

    Try this:

    cloneStore : function(originStore, newStore) {
    
        if (!newStore) {
            newStore = Ext.create('Ext.data.Store', {
                model : originStore.model
            });
        } else {
            newStore.removeAll(true);
        }
    
        var records = [], originRecords = originStore.getRange(), i, newRecordData;
        for (i = 0; i < originRecords.length; i++) {
            newRecordData = Ext.ux.clone(originRecords[i].copy().data);
            newStore.add(new newStore.model(newRecordData, newRecordData.id));
        }
    
        newStore.fireEvent('load', newStore);
    
        return newStore;
    }
    

    Note: Ext.ux.clone is a separated plugin (you will find it) which makes a deep clone of an object. Maybe, Ext JS 4 provides a familiar thing, I don’t know.. I’m using this special clone since Ext JS 3.x

    It is possible that it is required to specify the proxy memorywhen creating a new store (I’m not sure right now because I’m using always the “provided” way.

    ExtJS 4.x solution

    function deepCloneStore (source) {
        var target = Ext.create ('Ext.data.Store', {
            model: source.model
        });
    
        Ext.each (source.getRange (), function (record) {
            var newRecordData = Ext.clone (record.copy().data);
            var model = new source.model (newRecordData, newRecordData.id);
    
            target.add (model);
        });
    
        return target;
    }
    
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