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Home/ Questions/Q 3627496
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T23:53:45+00:00 2026-05-18T23:53:45+00:00

I’m trying to figure out how to do a left-associative expression where recursive (not-enclosed

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I’m trying to figure out how to do a left-associative expression where recursive (not-enclosed in anything) expressions are possible. For example, I’d like to do:

expr + OP + expr

that parses 2 operations like 1 x 2 x 3 into (expr OP expr) OP expr result.

If I try to prevent expr parsing from infinite recursion, i can do something like:

expr -> Group(simple_expr + OP + expr)
      | simple_expr

but then I’d get the expr OP (expr OR expr) result.

How do I force left-side binding?

Edit: I know about the operatorPrecedence but when the operator is "IS" + Optional("NOT") or similar, it doesn’t seem to match properly.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T23:53:46+00:00Added an answer on May 18, 2026 at 11:53 pm

    Here is an example parse action that will take the flat lists of tokens and nest them as if parsed left-recursively:

    from pyparsing import *
    
    # parse action -maker
    def makeLRlike(numterms):
        if numterms is None:
            # None operator can only by binary op
            initlen = 2
            incr = 1
        else:
            initlen = {0:1,1:2,2:3,3:5}[numterms]
            incr = {0:1,1:1,2:2,3:4}[numterms]
    
        # define parse action for this number of terms,
        # to convert flat list of tokens into nested list
        def pa(s,l,t):
            t = t[0]
            if len(t) > initlen:
                ret = ParseResults(t[:initlen])
                i = initlen
                while i < len(t):
                    ret = ParseResults([ret] + t[i:i+incr])
                    i += incr
                return ParseResults([ret])
        return pa
    
    
    # setup a simple grammar for 4-function arithmetic
    varname = oneOf(list(alphas))
    integer = Word(nums)
    operand = integer | varname
    
    # ordinary opPrec definition
    arith1 = operatorPrecedence(operand,
        [
        (None, 2, opAssoc.LEFT),
        (oneOf("* /"), 2, opAssoc.LEFT),
        (oneOf("+ -"), 2, opAssoc.LEFT),
        ])
    
    # opPrec definition with parseAction makeLRlike
    arith2 = operatorPrecedence(operand,
        [
        (None, 2, opAssoc.LEFT, makeLRlike(None)),
        (oneOf("* /"), 2, opAssoc.LEFT, makeLRlike(2)),
        (oneOf("+ -"), 2, opAssoc.LEFT, makeLRlike(2)),
        ])
    
    # parse a few test strings, using both parsers
    for arith in (arith1, arith2):
        print arith.parseString("A+B+C+D+E")[0]
        print arith.parseString("A+B+C*D+E")[0]
        print arith.parseString("12AX+34BY+C*5DZ+E")[0]
    

    Prints:

    (normal)

    ['A', '+', 'B', '+', 'C', '+', 'D', '+', 'E']
    ['A', '+', 'B', '+', ['C', '*', 'D'], '+', 'E']
    [['12', 'A', 'X'], '+', ['34', 'B', 'Y'], '+', ['C', '*', ['5', 'D', 'Z']], '+', 'E']
    

    (LR-like)

    [[[['A', '+', 'B'], '+', 'C'], '+', 'D'], '+', 'E']
    [[['A', '+', 'B'], '+', ['C', '*', 'D']], '+', 'E']
    [[[[['12', 'A'], 'X'], '+', [['34', 'B'], 'Y']], '+', ['C', '*', [['5', 'D'], 'Z']]], '+', 'E']
    
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