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Home/ Questions/Q 7045583
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T02:32:53+00:00 2026-05-28T02:32:53+00:00

I’m trying to fill 100% of the viewport in WebKit (Chrome) using maths .

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I’m trying to fill 100% of the viewport in WebKit (Chrome) using maths.

What I’m doing right now is counting the number of elements and dividing that into 100 and then setting all of the widths for the elements to the resulting percentage, following the basic plan of liquid elements.

The problem is that as the number of elements gets very high, but even after the first few are added, there quickly begins to be an issue where a large amount of space opens up on the right of the elements as the browser fights between percentages, pixels, and rounding.

So my question is, how might you go about taking a variable number of elements and ensuring that the entire viewport is filled?

CSS and Javascript are both fair game, but I would prefer to avoid jQuery unless it has an incredibly simple solution. However, if you can only do it through jQuery, even if it’s longer, post it anyway and I can see if I can unravel it.

I should stipulate clearly that this solution must work for a liquid layout. The browser and the containing elements must be able to resize down to about 200px. Any solution that depends on cutting apart a known quantity of pixels won’t work for me.

I’ve published a test site if you’re not sure what I mean.

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  1. Editorial Team
    Editorial Team
    2026-05-28T02:32:54+00:00Added an answer on May 28, 2026 at 2:32 am

    display: table to the rescue!

    The problem with my initial solution, of course, is that the elements are floated left and then given explicit widths. The upshot is that as the browser rounds the widths to the nearest pixel, you get jumpiness on the right-hand side of the viewport as you slowly gain and loose total pixels.

    The beauty of a table is that the browser already knows that each cell should fill exactly its portion of 100% of the table’s width. If the table is 100% as wide as the viewport and you have 4 cells each cell will be 25% of the viewport. Add another and the browser gives each cell as close as it can to 20% of the viewport. It handles all rounding for you so at any given time some of the cells may be a pixel bigger than other ones but the difference is always a pixel and the viewport is still filled perfectly.

    The only downside I can see is that you need to have elements that you can put stuff in to be able to use display: table-cell because table cells are non-block level elements and can’t be given explicit widths. They need content in order to display. Luckily for me, I can have a ul with li elements filled with a elements and thus I can hang the CSS nicely.

    For the list

    <ul class="mess">
      <li class="mess-part"><a href="#"></a></li>
      <li class="mess-part"><a href="#"></a></li>
      <li class="mess-part"><a href="#"></a></li>
      <li class="mess-part"><a href="#"></a></li>
    </ul>
    

    You need to apply the styles

    .mess { display: table; height: 300px; width: 100%; margin: 0; padding: 0; }
    .mess-part { display: table-cell; height: 100%; }
    

    And you get a nice, pretty, 100% wide, always filled, liquid-layout spread of elements.

    I’ve published an interactive version of the fix.

    Pretty neat, eh?

    HT to this question for getting the gears in my head turning.

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