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Home/ Questions/Q 8811709
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T03:25:56+00:00 2026-06-14T03:25:56+00:00

I’m trying to filter this code for the data between <cookie> & </cookie> and

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I’m trying to filter this code for the data between <cookie> & </cookie> and the data between account-id=" & " (the trailing quote)

<?xml version="1.0" encoding="utf-8"?>
<results>
 <status code="ok"/>
 <common locale="en" time-zone-id="85">
  <cookie>na3breezfxm5hk6co2kfzuxq</cookie>
  <date>2012-11-11T16:26:52.713+00:00</date>
  <host>http://meet97263421.adobeconnect.com</host>
  <local-host>pacna3app09</local-host>
  <admin-host>na3cps.adobeconnect.com</admin-host>
  <url>/api/xml?action=common-info</url>
  <version>8.2.2.0</version>
  <tos-version>7.5</tos-version>
  <product-notification>true</product-notification>
  <account account-id="1013353222"/>
  <user-agent>curl/7.24.0 (x86_64-apple-darwin12.0) libcurl/7.24.0 OpenSSL/0.9.8r zlib/1.2.5</user-agent>
 </common>
</results>

Any help would be appreciated.

EDIT

This is the curl command I run to return the above xml.

curl -s http://meet97263421.adobeconnect.com/api/xml?action=common-info
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T03:25:58+00:00Added an answer on June 14, 2026 at 3:25 am

    In general, regexes (and therefore grep) aren’t well-suited to parsing XML, but if you can guarantee the input is well-formatted and consistent you can do this most easily with grep‘s perl-style regexes (on systems whose grep has them):

    grep -oP '(?<=<cookie>).*?(?=</cookie>)'
    grep -oP '(?<=account-id=").*?(?=")'
    

    If you want them in the same command, you can separate them with a |, but then you have to tell which matches which.

    grep -oP '(?<=<cookie>).*?(?=</cookie>)|(?<=account-id=").*?(?=")'
    
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