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Home/ Questions/Q 7685335
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T19:13:42+00:00 2026-05-31T19:13:42+00:00

I’m trying to find a way to change/update a model inside a collection without

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I’m trying to find a way to change/update a model inside a collection without first explicitly initializing it.

The idea is that I’m createing a new collection instance by passing a hash of objects to it. I am assuming that Backbone automagically creates model instances for each object (am I right?).
Now, if this is true, I should somehow be able to change / update the model in the collection, shouldn’t I?

I have tried this, but it doesn’t work:

serie = view.collection.get(serie_id);
serie.set({
    name: view.$('.series-name').val(),                 
    format: view.$('.series-format').val(),
    number: view.$('.series-number').val()
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T19:13:43+00:00Added an answer on May 31, 2026 at 7:13 pm

    I don’t think you can just pass in any hash of objects and have Collection automagically create models. You need to instantiate models and pass them in as a models array.

    I think what you’re talking about is something like this though:

    ViewCollection = Backbone.Collection.extend({
        model: Serie
    });
    
    myViewCollection = new ViewCollection();
    
    // This will automatically create a Serie model instance and add it in your collection
    myViewCollection.create({
        name: 'something',
        format: 'something',
        number: 'something'
    });
    

    When you specify the model attribute on the collection Class, then you can utilize the create() function of your collection and it will instantiate a model just by passing a hash of attributes.

    If you set up your Serie model with some arbitrary default values, you could just run a loop and create a bunch of empty models. Then you could use the code you listed above to change those attributes using the .get(id) .set() methods. Although is there a good reason you want to do things this way?

    It feels like using the .create() method as needed would work for most use cases.

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