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Home/ Questions/Q 8069321
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T12:59:19+00:00 2026-06-05T12:59:19+00:00

i’m trying to find the docs for the function in Inside python. It is

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i’m trying to find the docs for the function

in

Inside python. It is very hard because the search engine can’t function with a word like in.

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  1. Editorial Team
    Editorial Team
    2026-06-05T12:59:21+00:00Added an answer on June 5, 2026 at 12:59 pm

    “in” is not a function. Its a built-in keyword. Using it can trigger the target objects __contains__()

    http://docs.python.org/reference/datamodel.html#object.contains

    >>> l = ['a']
    >>> l.__contains__('a')
    True
    >>> 'a' in l
    True
    

    I say “can trigger” because the logic has different ways it might resolve under the hood:

    For objects that don’t define __contains__(), the membership test
    first tries iteration via __iter__(), then the old sequence iteration
    protocol via __getitem__()

    Note that this example only covers a membership test, as opposed to using it to loop over an iterable.

    To illustrate how in is resolved during a loop operation, an iterator is first looked for using __iter__() :

    l = range(5)
    l.__iter__()
    # <listiterator object at 0x1004e4fd0>
    it = l.__iter__()
    it.next()
    # 0
    it.next()
    # 1
    it.next()
    # 2
    

    In the event that the object does not have an __iter__() defined, it will try using the older __getitem__(). Take a string, for instance, which does not have an __iter__(). This is just an illustration…

    >>> i = 0
    >>> s = "string"
    >>> while i < len(s):
    ...  print s.__getitem__(i)
    ...  i+=1
    ... 
    s
    t
    r
    i
    n
    g
    

    And to show a similar iterator (generator here):

    gen = (s.__getitem__(i) for i in xrange(len(s)))
    # <generator object <genexpr> at 0x1004e8780>
    gen.next()
    # 's'
    gen.next()
    # 't'
    gen.next()
    # 'r'
    
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