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Home/ Questions/Q 8543243
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T12:15:21+00:00 2026-06-11T12:15:21+00:00

I’m trying to finish a program that converts text2bin and bin2text among other things,

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I’m trying to finish a program that converts text2bin and bin2text among other things, but I have a problem with the bin2text function, but only with some characters.
This is the part that is giving me problems:

def bin2text(self):                 
  cadena2=' '

  self.ventana.caja1.text()
  split=[self.ventana.caja1.text()[x:x+8] for x in range(0,len(self.ventana.caja1.text()),8)]

   for i in splits:
       cadena2=cadena2+chr(int(i,2))

   self.ventana.caja2.setText(cadena2)

I’m getting the error:

Invalid literal for int() with base 2 '100000 1.... '

on the line

cadena2=cadena2+chr(int(i,2)) 

(The ellipses dots aren’t actually a part of the error but there’s an arrow in the way in the figure)

when I try to go from binary to text, using “space” or any sign that the passing of ASCII to Bin, the number consists of six digits, I get the error. Seven or eight digit numbers work.

I need to know a how to add a 0 at the beginning of this series(0100000), to fix it

See figures below:
no problem

with problem

this is the problem

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  1. Editorial Team
    Editorial Team
    2026-06-11T12:15:22+00:00Added an answer on June 11, 2026 at 12:15 pm

    try this:

    splits = self.ventana.caja1.text().split() #split by whitespace
    
    for i in splits:
       cadena2=cadena2+chr(int(i,2))
    

    The problem is not the number of digits, the problem is the whitespace within the string you sent to ‘int’

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