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Home/ Questions/Q 8860615
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T15:17:51+00:00 2026-06-14T15:17:51+00:00

I’m trying to get a images file extension and add some random number. Like

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I’m trying to get a images file extension and add some random number. Like 348678423.jpeg, 343344343.jpg, 32434343.gif, 3434343.png etc..

So following is my php code:

function getExtension($str)
{
     $i = strrpos($str,".");
 if (!$i) { return ""; }
 $l = strlen($str) - $i;
 $ext = substr($str,$i+1,$l);
 return $ext;
}
  @$extension = getExtension($file);
   $extension = strtolower($extension);
  $image_named_uniq = uniqid().'.'.$extension;  

But when i echo this variable $image_named_uniq it’s just show the random number, Like: 50aa5a2e0f425. It’s should be show 50aa5a2e0f425.jpg etc..

What is wrong in my code?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T15:17:52+00:00Added an answer on June 14, 2026 at 3:17 pm

    The answer posted by @jereon is correct, and the easiest way to do this.

    However, if you would like to extract more information about the file without using explode and end, you can simply use the PHP built in pathinfo() function.

    Reference: pathinfo()

    <?php
        $path_parts = pathinfo('/www/htdocs/inc/lib.inc.php');
    
        echo $path_parts['dirname'], "\n";
        echo $path_parts['basename'], "\n";
        echo $path_parts['extension'], "\n";
        echo $path_parts['filename'], "\n"; // since PHP 5.2.0
    ?>
    

    This will return

    /www/htdocs/inc
    lib.inc.php
    php
    lib.inc
    

    As $filename is an array, you need to loop through it in order to read it into pathinfo(). This can be done very easily using a foreach loop like so:

    // Loop through the filenames array
    foreach($filename as $value){
        // Retrieve the path parts of each individual file
        $path_parts[] = pathinfo($value);
    }
    
    // Write out the path parts array
    print_r($path_parts);
    
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