Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 327797
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 12, 20262026-05-12T09:26:08+00:00 2026-05-12T09:26:08+00:00

I’m trying to get a list of all users and all groups on Mac

  • 0

I’m trying to get a list of all users and all groups on Mac OS X 10.5+. How can I do this?

For example, the list of all users on my machine should return:
_amavisd, _appowner, _appserver, _ard, _atsserver, _calendar, _carddav, _clamav, _coreaudiod, _cvmsroot, _cvs, _cyrus, _devdocs, _dovecot, _eppc, _installer, _jabber, _lda, _locationd, _lp, _mailman, _mcxalr, _mdnsresponder, _mysql, _pcastagent, _pcastserver, _postfix, _qtss, _sandbox, _screensaver, _securityagent, _serialnumberd, _softwareupdate, _spotlight, _sshd, _svn, _teamsserver, _timezone, _tokend, _trustevaluationagent, _unknown, _update_sharing, _usbmuxd, _uucp, _windowserver, _www, _xgridagent, _xgridcontroller, daemon, dave, nobody, root (that was painstakingly compiled manually).

How can I get that list (and the corresponding list of all groups) programmatically? I’m open to alternative (non-c based) solutions, such as Applescript, commandline, etc.


Update a long time later

TALlama’s answer prompted me to investigate the API to Open Directory, and I found that this list can be easily acquired programmatically:

#import <OpenDirectory/OpenDirectory.h>
ODSession *s = [ODSession defaultSession];
ODNode *root = [ODNode nodeWithSession:s name:@"/Local/Default" error:nil];
ODQuery *q = [ODQuery queryWithNode:root forRecordTypes:kODRecordTypeUsers attribute:nil matchType:0 queryValues:nil returnAttributes:nil maximumResults:0 error:nil];

NSArray *results = [q resultsAllowingPartial:NO error:nil];
for (ODRecord *r in results) {
    NSLog(@"%@", [r recordName]);
}

That will log the usernames of every user on the system. Substituting in kODRecordTypeGroups will get you the list of all the groups.

The -[ODQuery resultsAllowingPartial:error:] method is a blocking call, so you’d either want to execute this code on a background thread, or use an <ODQueryDelegate> to aggregate the results.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-12T09:26:08+00:00Added an answer on May 12, 2026 at 9:26 am

    The tool you want is almost certainly dscl. The shortest way to do it was already pointed out:

    $ dscl . list /users
    $ dscl . list /groups
    

    If you want to output information about each user, though, use readall:

    $ dscl . readall /users
    $ dscl . readall /groups
    

    And if you need to programatically parse said information, use -plist to make your life easier:

    $ dscl -plist . readall /users
    $ dscl -plist . readall /groups
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
Does anyone know how can I replace this 2 symbol below from the string
I'm new to using the Perl treebuilder module for HTML parsing and can't figure
Basically, what I'm trying to create is a page of div tags, each has
I am trying to understand how to use SyndicationItem to display feed which is
link Im having trouble converting the html entites into html characters, (&# 8217;) i
For some reason, after submitting a string like this Jack’s Spindle from a text
this is what i have right now Drawing an RSS feed into the php,
I am trying to render a haml file in a javascript response like so:

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.