Question

I’m trying to get a match but am having trouble with the syntax, below I am using python but it can be any language, i just need the correct regex syntax:

import re
p = re.compile('foo%22([^%22])*')

input = "foo%22somedata%2Bgoeshere%22testbarbaz"

result = re.findall(p, input)

I’m trying to extract “somedata%2Bgoeshere”. Basically I want the stuff between the %22’s. So the regex I tried (above) isn’t working b/c that ‘not’ operator is saying ‘not %’, ‘not 2’, and ‘not 2’…I want to say, get anything until you see “%22”.

Thanks in advance.

Answer 1

Use positive lookahead:

>>> import re
>>> input = "foo%22somedata%2Bgoeshere%22testbarbaz"
>>> re.findall('foo%22.*?(?=%22)', input)
['foo%22somedata%2Bgoeshere']