Question

I’m trying to get json code from page.I use this

private function __ajax_admin_search($username = '')
{
   $result = $this->admin_login->Admin_Username_Ajax($username);
   $count = count($result);
   for ($i = 0;$i < $count;$i++)
      $arr[$i] = $result[$i]->username;
   echo (json_encode($arr));
}

And try to show it by jQuery and JavaScript

$("#AdminSearch").bind("change keyup", function() { 
           var url = "http://localhost/PmMusic/index.php/admin/ajax/admin_search/"+$("#AdminSearch").val();
            $.getJSON(url,function(data){
                if (data.length == 0) // or arr == null
                {
                    $("#AutoSearch").hide(1000);
                }
                else
                {
                    $("#AutoSearch").show(1000);    
                }
            });

        });

Now my problem is,I can’t detect when __ajax_admin_search doesn’t find any result and first if (in JavaScript) doesn’t be TRUE(always it’s FALSE).
how Can I detect in JavaScript when my php code doesn’t find any result in database.

Answer 1

Make sure to initialise $arr = Array(); before your for loop.

Then, the PHP script will return [] as the JSON object, which you can detect in JavaScript without problems.