Question

I’m trying to get lua 5.1 to execute a line which is just a call to one of my c++ functions "Assail" I don’t understand why it does not work, can anybody point out the mistakes?

this is the Assail Function:

static int Assail(lua_State *L)
{
    cout << "test" << endl;
    return 1;
}

I’m trying to call do_string like this:

L = lua_open();
luaL_openlibs(L);
lua_register(L, "Assail", Assail);
luaL_dostring(L, "s = Assail()");   
lua_close(L);

any help is appreciated.

Answer 1

Since you’re writing this in C++, name mangling is applied to the function, so it will have a special name in the final executable/library that is different from that Lua would expect. You can resolve this by changing its linkage to C using the extern keyword:

extern "C" int Assail(lua_State *L);

extern "C" int Assail(lua_State *L)
{
    // code here
}