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Editorial Team
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Asked: 2026-06-12T16:16:54+00:00

I’m trying to get the ASIN of some Amazon items. I found a pattern:

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I’m trying to get the ASIN of some Amazon items. I found a pattern: the ASIN is always after “/dp/”. How can I extract the ASIN (B003CP0V6S) from that string?
I’m using ruby

url = "http://www.amazon.it/Calvin-Klein-Deluxe-K0S21120--Orologio/dp/B003CP0V6S/ref=lp_1597641031_1_8?ie=UTF8&qid=1349983393&sr=1-8"
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1 Answer

  1. Editorial Team
    str = "http://www.amazon.it/Calvin-Klein-Deluxe-K0S21120--Orologio/dp/B003CP0V6S/ref=lp_1597641031_1_8?ie=UTF8&qid=1349983393&sr=1-8"
(match = str.match(/\/dp\/([^\/]*)/)) && match[1]
# => "B003CP0V6S"
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