Question

I’m trying to get the cureent url and send that through in a link and I’m stuck. The link displays but it’s missing the url that I want to include (content in the code sample here)

'href' => ( "http://chart.apis.google.com/chart?cht=qr&chs=300x300&choe=UTF-8&chld=H&chl='.$content .'")

Answer 1

Your quotes aren’t correct:

'href' => ( "http://chart.apis.google.com/chart?cht=qr&chs=300x300&choe=UTF-8&chld=H&chl=".$content)

You should also use urlencode() and urldecode() to ensure the $content variable is properly formatted

Edit
Try this then:

$currentUrl = rawurlencode($_SERVER['PATH_INFO']);
$newUrl = "http://chart.apis.google.com/chart?cht=qr&chs=300x300&choe=UTF-8&chld=H&chl=";

header("Location: $newUrl.$currentUrl");

//Not sure if path_info will always contain the full url but there are lots of functions on the web to grab the current url that you can google for.