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Home/ Questions/Q 8486095
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T20:50:43+00:00 2026-06-10T20:50:43+00:00

I’m trying to get the top node of a chain in getTopParent() . When

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I’m trying to get the top node of a chain in getTopParent(). When I print out self.name, it indeed prints out the name of the parent instance; however, when I return self, it returns None. Why is this?

class A:
    def __init__( self, name ):
        self.name = name
        self.owner = None
    def setChild( self, l ):
        l.owner = self
    def getTopParent( self ):
        if( self.owner == None ): # None == top parent
            print( "Got top: %s" % self.name )
            return self
        else:
            print( "checking %s" % self.name )
            self.owner.getTopParent()

a = A( "parent" )
b = A( "child1" )
c = A( "child2" )
d = A( "child3" )
a.setChild( b )
b.setChild( c )
c.setChild( d )

print( d.getTopParent() )
>>> checking child3
    checking child2
    checking child1
    Got top: parent
    None
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  1. Editorial Team
    Editorial Team
    2026-06-10T20:50:45+00:00Added an answer on June 10, 2026 at 8:50 pm

    You need to return self.owner.getTopParent()!

    In Python, you must actually use the return statement to return something from a function, otherwise None is returned.

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