Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 216153
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 11, 20262026-05-11T18:32:16+00:00 2026-05-11T18:32:16+00:00

I’m trying to get the week range using Sunday as the start date, and

  • 0

I’m trying to get the week range using Sunday as the start date, and a reference date, say $date, but I just can’t seem to figure it out.

For example, if I had $date as 2009-05-01, I would get 2009-04-26 and 2009-05-02. 2009-05-10 would yield 2009-05-10 and 2009-05-16. My current code looks like this (I can’t remember where I lifted it from, as I forgot to put down the url in my comments):

function x_week_range(&$start_date, &$end_date, $date)
{
    $start_date = '';
    $end_date = '';
    $week = date('W', strtotime($date));
    $week = $week;

    $start_date = $date;

    $i = 0;
    while(date('W', strtotime("-$i day")) >= $week) {
        $start_date = date('Y-m-d', strtotime("-$i day"));
        $i++;
    }

    list($yr, $mo, $da) = explode('-', $start_date);

    $end_date = date('Y-m-d', mktime(0, 0, 0, $mo, $da + 6, $yr));
}

I realized all it did was add 7 days to the current date. How would you do this?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-11T18:32:16+00:00Added an answer on May 11, 2026 at 6:32 pm

    I would take advantange of PHP’s strtotime awesomeness:

    function x_week_range(&$start_date, &$end_date, $date) {
        $ts = strtotime($date);
        $start = (date('w', $ts) == 0) ? $ts : strtotime('last sunday', $ts);
        $start_date = date('Y-m-d', $start);
        $end_date = date('Y-m-d', strtotime('next saturday', $start));
    }
    

    Tested on the data you provided and it works. I don’t particularly like the whole reference thing you have going on, though. If this was my function, I’d have it be like this:

    function x_week_range($date) {
        $ts = strtotime($date);
        $start = (date('w', $ts) == 0) ? $ts : strtotime('last sunday', $ts);
        return array(date('Y-m-d', $start),
                     date('Y-m-d', strtotime('next saturday', $start)));
    }
    

    And call it like this:

    list($start_date, $end_date) = x_week_range('2009-05-10');
    

    I’m not a big fan of doing math for things like this. Dates are tricky and I prefer to have PHP figure it out.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 165k
  • Answers 165k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer Categories extend the original class, but they don't subclass it,… May 12, 2026 at 12:54 pm
  • Editorial Team
    Editorial Team added an answer Haven't tested this, but it's something like: RewriteRule \.php$ -… May 12, 2026 at 12:54 pm
  • Editorial Team
    Editorial Team added an answer "0:0:0:0:0:0:0:1" is the IPv6 loopback address as defined in RFC… May 12, 2026 at 12:54 pm

Related Questions

I ran into a problem. Wrote the following code snippet: teksti = teksti.Trim() teksti
I am currently running into a problem where an element is coming back from
Seemingly simple, but I cannot find anything relevant on the web. What is the
Does anyone know how can I replace this 2 symbol below from the string
Configuring TinyMCE to allow for tags, based on a customer requirement. My config is

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.