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Home/ Questions/Q 7530053
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T04:48:23+00:00 2026-05-30T04:48:23+00:00

I’m trying to implement a file watcher that will raise an event if the

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I’m trying to implement a file watcher that will raise an event if the file content was changed.
The problem that once the file I am watching was modified, I am getting 2 events.
(I want to get it only once)

_automationStatusWatcher = new FileSystemWatcher(fileInfo.Directory.FullName,
                                                 fileInfo.Name);
_automationStatusWatcher.NotifyFilter = NotifyFilters.LastWrite;
_automationStatusWatcher.Changed += OnAutomationStatusChanged;
_automationStatusWatcher.EnableRaisingEvents = true;

The file that i’m watching is not intended to be recreated/moved/deleted/whatever. its purpose is to be an xml database file that i need to monitor it once it changes. i want to get only 1 event when the file is modified and to ignore the other events.

How can I do that?

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  1. Editorial Team
    Editorial Team
    2026-05-30T04:48:24+00:00Added an answer on May 30, 2026 at 4:48 am

    Manual:

    Note

    Common file system operations might raise more than one event. For example, when a file is moved from one directory to another, several OnChanged and some OnCreated and OnDeleted events might be raised. Moving a file is a complex operation that consists of multiple simple operations, therefore raising multiple events. Likewise, some applications (for example, antivirus software) might cause additional file system events that are detected by FileSystemWatcher.

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