Question

I’m trying to implement a generic linked list. The struct for the node is as follows –

typedef struct node{
        void *data;
        node *next;      
};

Now, when I try to assign an address to the data, suppose for example for an int, like –

int n1=6;
node *temp;
temp = (node*)malloc(sizeof(node));
temp->data=&n1;

How can I get the value of n1 from the node? If I say –

cout<<(*(temp->data));

I get –

`void*' is not a pointer-to-object type 

Doesn’t void pointer get typecasted to int pointer type when I assign an address of int to it?

Answer 1

You must first typecast the void* to actual valid type of pointer (e.g int*) to tell the compiler how much memory you are expecting to dereference.